What is the torque on the bolt due to the worker and the weight of the beam?

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The discussion focuses on calculating the torque on a bolt due to a 500 kg steel beam and a 70 kg worker standing at the beam's end. The torque from the beam is calculated using its weight acting at the midpoint, resulting in 6350.4 N*m, while the torque from the worker is 2469.6 N*m. The total torque around the bolt is then determined to be 8820 N*m. A correction is noted regarding the beam's mass, emphasizing it should be 500 kg instead of 360 kg. The calculations and reasoning about the beam's mass being concentrated at the midpoint are confirmed as correct.
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Homework Statement


A 3.60-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70kg construction worker stands at the far end of the beam

What is the magnitude of the torque about the bolt due to the worker and the weight of the beam?
(there was no diagram)

Homework Equations


torque = m*d

The Attempt at a Solution


I just summed the torques around the bolt and considered the beam as having all its mass at its center:
torque from beam: t = 360kg(9.8)(1.8m) = 6350.4N*m
torque from person: t = 70kg(9.8)(3.6) = 2469.6N*m
2469.6N*m + 6350.4N*m = 8820N*m

Is this correct and is my reasoning about beam as having its mass at midpoint correct? thanks for any help
 
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Yes but the beam is 500kg not 360kg
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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