1. The problem statement, all variables and given/known data Sunlight falls on a concave mirror and forms an image 3.0 cm from the mirror. If an object 24 mm high is placed 12.0 cm from the mirror, where will its image be formed? a. Use a ray diagram b. Use the lens/ mirror equation c. How high is the image? 2. Relevant equations (1/f)= (1/di) + (1/do) 3. The attempt at a solution Knowing that in the case of the sun, all rays of sunlight are essentially parallel to the principle axis because of the huge distance between the sun and the earth, I assume that all light of the sum converge at the focal point. Thus, the image's location as formed by the sun marks the focal point of the mirror. Therefore, f= 3cm, di= ?, do=12cm. I use the lens/mirror equation: (1/f)= (1/di) + (1/do) 1/3cm = (1/di) + 1/12cm 1/4cm = 1/di di= 4 cm Consulting the ray diagram that I drew, I see that the image would be inverted and is between the focal point and the object's location .. . ^ Is that correct? If so, is it possible to find this value simply by drawing a not-to-scale diagram? I dont understand how I can use a ray diagram. . . I'm so confused; thank you in advance!!!