The Problem: A plane is dropping supplies to a clearing in the forest. The plane will approach the clearing at an altitude of 150 m while flying level at 40 m/s. Why can't the plane drop the supplies while directly over the clearing and at what distance should it release them to arrive to its destination? I've worked out 2 answers and I'm not entirely sure which is the correct one. Relevant Equations: d=vt+1/2at^2 d=1/2at^2 d=vt The Attempt: Solution 1 d=vt+1/2at^2 0=(40 m/s)t + 1/2(-9.8m/s^2)t^2 0=t (40 m/s - 4.9 m/s^2 t) 40 m/s = 4.9 t t= 8.2 s d=(40 m/s)(8.2 s) d=328 m Solution 2 d=1/2at^2 150 m=4.9 t^2 t= 5.5 s d=vt d=(40 m/s)(5.5 s) d=220 m Something is telling me I'm wrong/approaching this incorrectly/way off. So please, some one...help!