Quantum Tunneling of a conduction electron in Copper

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SUMMARY

The discussion centers on estimating the penetration depth (Δx) of a conduction electron in Copper (Cu) using quantum tunneling principles. The work function of Copper is established at 4 eV, which is critical for determining the energy (E) of the electron. The penetration depth is calculated using the formula Δx = ħ/(2sqrt(2m(V-E))), where V is the potential energy (4 eV) and E is the energy of the electron. The participant seeks clarification on how to derive the electron's energy value in relation to the work function.

PREREQUISITES
  • Understanding of quantum mechanics, specifically wave functions and tunneling.
  • Familiarity with the concept of work function in solid-state physics.
  • Knowledge of the Schrödinger equation and its applications.
  • Basic principles of electron behavior in conductive materials.
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  • Research the relationship between work function and electron energy in metals.
  • Study the derivation of the wave function for quantum tunneling scenarios.
  • Learn about the implications of potential wells in quantum mechanics.
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Physics students, researchers in quantum mechanics, and professionals studying electron behavior in conductive materials will benefit from this discussion.

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Homework Statement


A conduction electron moves through a block of Cu until it reaches the surface. At the surface the electron feels a strong force exerted by the nonuniform charge distribution in that region. This force tends to attract the electron back into the metal which is what causes the conduction electron to remain bound to the metal. Given that the work function of the metal is 4 eV estimate the distance x that the electron can penetrate outside of the Cu block.

Homework Equations


Wave function = Ψ(x) = De^(-kx)
Probability of tunneling = P = |Ψ(x)^2
Wave number k = sqrt(2m(V-E))/ħ

The Attempt at a Solution


I am confident on how the penetration depth is calculated as it can be calculated using the following steps;

Compare probability at x=0 and x = Δx where Δx is the point where the probability of finding a particle is 1/e of its original value.
This gives;
1/e * |Ψ(0)|^2 = |Ψ(Δx)|^2
D^2e^(-2k*0) * 1/e = D^2e^(-2k(Δx))
1/e = e^(-2k(Δx))
-1 = -2k(Δx)
Δx = 1/2k
Δx = ħ/(2sqrt(2m(V-E)))

We know the potential is 4eV from the question, but I don't know how the energy of the electron, E, is obtained and any help on where the value for E would be appreciated..

Thank you in advance.
 
Last edited:
Physics news on Phys.org
Hint: what does the work function tell you?
(Not the depth of the potential well.)
 

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