Superposition in separation method of variables

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The discussion centers around the application of superposition in solving boundary value problems with varying charge configurations. It questions the validity of using superposition for different boundary conditions, specifically regarding the potential solutions at different faces of a cube. The conversation acknowledges that the exercise text likely supports the feasibility of the proposed solution. Participants emphasize the importance of understanding the relationship between the solutions at different boundaries. The thread concludes with a recognition that further elaboration is necessary to fully address the problem.
Celso
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Homework Statement
In a cube, the specified boundary counditions are V = ##V_{0}## in the ##z = 0## and ##z = d## planes and ##V = 0## for the other sides. Knowing the solution for when only one of the z planes is kept at ##V = V_{0}## how is it possible to use superposition to know ##V(r)## in this situation?
Relevant Equations
##\nabla^2 V = 0##
Each different boundary condition means a different charge configuration, how can this problem be solved using superposition?
 
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Seems very unlikely to me. Anyone says it can be ?
 
Let ##\Phi_0(x,y,z)## = solution when only the face at z = 0 is at ##V_0##.
Let ##\Phi_d(x,y,z)## = solution when only the face at z = d is at ##V_0##.
Assuming that the side of the cube is ##d##, isn't it true that ##\Phi_d(x,y,z)=\Phi_0(x,y,d-z)##?
 
Can you create a square pulse using two step functions? That is the crux of the question. I won't give the answer, as it is homework.
 
BvU said:
Seems very unlikely to me. Anyone says it can be ?
Ah! I get it: the exercise text as it was given to you says so o:) . Then it is most likely true, hmm ?
And @kuruman is giving you (much) more than just a hint !
 
BvU said:
Ah! I get it: the exercise text as it was given to you says so o:) . Then it is most likely true, hmm ?
And @kuruman is giving you (much) more than just a hint !
It's easy to assume that the problem is asking for the solution. Perhaps I was overly generous when I posted but I wanted to point OP in the right direction and there is still quite a bit to be said to complete a formal answer.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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