Is the vector superfield in superspace a physical degree of freedom?

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SUMMARY

The discussion centers on the construction of a vector superfield using the expression from Bailin-Love, page 59, equation 3.23, which is defined as a chiral field minus an anti-chiral superfield. It is concluded that this vector superfield does not possess a kinetic term (WW) as indicated by expression 3.37, where all terms in the kinetic expression evaluate to zero. The confusion arises from the multiple representations of the vector field V, which includes the field strength tensor V_{\mu\nu} defined in 3.37. Ultimately, the vector superfield does not correspond to a physical degree of freedom, as the gauge field component is purely gauge.

PREREQUISITES
  • Understanding of vector superfields and their construction in superspace.
  • Familiarity with chiral and anti-chiral superfields.
  • Knowledge of the field strength tensor and its role in gauge theories.
  • Proficiency in interpreting equations from advanced theoretical physics texts, specifically Bailin-Love.
NEXT STEPS
  • Study the implications of gauge transformations on vector superfields.
  • Examine the role of kinetic terms in supersymmetric theories.
  • Explore the relationship between chiral fields and physical degrees of freedom in superspace.
  • Review the derivation and applications of the field strength tensor V_{\mu\nu} in gauge theories.
USEFUL FOR

The discussion is beneficial for theoretical physicists, particularly those specializing in supersymmetry and gauge theories, as well as graduate students seeking to deepen their understanding of vector superfields and their properties in superspace.

Neitrino
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HI,

We can construct vector superfield by chiral field minus anti chiral super field (example Bailin-Love page 59 expression 3.23)

So does this vector superfield have a kinetic term-WW ? since the for the kinetic term we have expression 3.37 and it seems that if vector superfield is defined as in 3.23 then all terms in kinetic expression are zero.

Thank you
 

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Neitrino said:
HI,

We can construct vector superfield by chiral field minus anti chiral super field (example Bailin-Love page 59 expression 3.23)

So does this vector superfield have a kinetic term-WW ? since the for the kinetic term we have expression 3.37 and it seems that if vector superfield is defined as in 3.23 then all terms in kinetic expression are zero.

Thank you

V_{\mu\nu} in 3.37 is the field strength tensor for the Lorentz vector field V_{\mu} appearing as the lowest component of V_{WZ} in 3.23. There are no extra \thetas appearing in the terms in 3.37. In the abelian theory considered there,

V_{\mu\nu} = \partial_\mu V_\nu - \partial_\nu V_\mu.

I think that your confusion is due to the fact that the authors are using V to represent at least 3 different but related objects.
 
Neitrino said:
HI,

We can construct vector superfield by chiral field minus anti chiral super field (example Bailin-Love page 59 expression 3.23)

So does this vector superfield have a kinetic term-WW ? since the for the kinetic term we have expression 3.37 and it seems that if vector superfield is defined as in 3.23 then all terms in kinetic expression are zero.

The confusion is that this is not a vector superfield with a propagating spin-1 component, rather the gauge field component is pure gauge. The point is that the combination "chiral field minus anti chiral super field" is precisely how a local gauge transformation acts on a vector superfield, so this is precisely the superspace generalization of writing

variation(A_mu) = del_mu phi

which does not describe a physical degree of freedom.
 
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