Suppose B is moving with speed v away from A

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SUMMARY

The discussion focuses on the application of K-calculus and Lorentz transformations in the context of special relativity. It establishes that the time observed by B for an explosion event occurring at A is given by the equation t' = γt, where γ is the Lorentz factor. The user clarifies that k does not equal γ, highlighting the distinction between the two concepts. The conversation concludes with a query about proving K-calculus geometrically, specifically regarding the translation of lengths along the ct and ct' axes.

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Students and professionals in physics, particularly those studying special relativity, K-calculus, and Lorentz transformations. This discussion is beneficial for anyone looking to deepen their understanding of time dilation and the effects of relative motion on time perception.

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Homework Statement




Hi guys, i have a very simple question here about K-calculus.

Suppose B is moving with speed v away from A.

At time = t, an explosion (event) occurs in A, sending light in all directions.

2dgs4e9.png



According to the K-Calculus,

The time the explosion occurred in B would be:

t' = kt


But, using lorentz transformations:

t' = γ(t - vx/c2)

Since x = 0,

t' = γt


But it is quite clear that k≠γ..



Nevermind, I have solved it:

Time light from event received by B ≠ Time of event

Bu rather, the observer takes into account and B compensates for the time needed for light from the event to travel to him:

t' = kt - (v/c)t'

t' = kt/(1 + β) = γt (Shown)
 
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Also on a side note, is it possible to prove the K-calculus using geometry? Which basically says that 'u' length along the ct axis would translate into 'k*u' length along the ct' axis..
 

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