Supremum and Infimum of a Set Containing Rational Numbers

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Homework Help Overview

The discussion revolves around finding the supremum and infimum of a set defined by rational numbers, specifically the set A = { m/n + 4m/n : m,n ∈ ℕ* }. Participants are exploring the implications of the notation and the nature of the elements within the set.

Discussion Character

  • Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the original poster's understanding of the notation and the elements of the set. There are discussions about whether to combine cases based on the relationships between m and n, and how to approach more complex sets.

Discussion Status

The discussion is ongoing, with participants providing clarifications and raising questions about the separation of cases in the problem. Some guidance has been offered regarding the exploration of elements in the set based on varying values of m and n.

Contextual Notes

There is a mention of potential complexity in similar problems, suggesting that the approach may vary depending on the specific set being analyzed. The notation and the definitions of the sets are under scrutiny, indicating a need for clarity in understanding the problem.

Felafel
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Homework Statement



Hello. I think I've managed to solve the exercise, but I'd like it to be checked and I'd also like to kow whether it is well-written and explained enough.

The problem is: find the supremum and infimum of this set:
A= \{ \frac{m}{n}+4\frac{m}{n} : m,n \in \mathbb{N}^*\}

The Attempt at a Solution



if m=n then 5 is the only element of the set. Therefore it is its minimum and maximum and also its supremum and infimum.
if m<n the infimum (and also the minimum) is ## \frac{17}{2} ## because the minimum values for m and n are 1 e 2.
if n<m the infimum is 4, for the same reason.
either when m<n or n<m the supremum is ## +\infty ##
 
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I think you are severely misunderstanding the notation. The notation

A=\{\frac{m}{n}+4\frac{m}{n} | m,n\in \mathbb{N}^*\}

means that we take all m and n in \mathbb{N}^*

For example:
  • 5 is an element of A since we can take m=n=1
  • 5/2 is an element of A since we can take m=1 and n=2
  • 10 is an element of A since we can take m=2 and n=1

These are three examples of elements in A. There are others.

We are letting m and n vary among the natural numbers. They can be truly anything.
 
ok, should I put the three cases m>n,m<n,m=n together then, and call infimum and supremum the highest and lowest values I find in the union?
 
Felafel said:
ok, should I put the three cases m>n,m<n,m=n together then, and call infimum and supremum the highest and lowest values I find in the union?

I don't really know why you are so set in separating the problem in cases m>n, m<n and n=m. That doesn't seem necessary here.

What elements of A do you get if m=1 and n varies?
What elements of A do you get if n=1 and m varies?
What does that tell you?
 
micromass said:
I don't really know why you are so set in separating the problem in cases m>n, m<n and n=m. That doesn't seem necessary here.

What elements of A do you get if m=1 and n varies?
What elements of A do you get if n=1 and m varies?
What does that tell you?

hahaha don't know why. but what if the set were more complicated? like
## B= \{ \frac{mn}{4m^2+n^2} : m \in \mathbb{Z}, n \in \mathbb{N}^* \} ##
wouldn't it be a good idea to separate the cases?
 
Felafel said:
hahaha don't know why. but what if the set were more complicated? like
## B= \{ \frac{mn}{4m^2+n^2} : m \in \mathbb{Z}, n \in \mathbb{N}^* \} ##
wouldn't it be a good idea to separate the cases?

It really depends on which sets you are given. Right now, I would be inclined to write

\frac{mn}{4m^2 + n^2} = 4\frac{n}{m} + \frac{m}{n}

So it would be a good idea to graph the function f(x)=4x+\frac{1}{x}.
 
enlightning, thank you!
 
In particular, suppose n= 1 and m= 100000. What member of the set would that give?
 

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