Hello, the problem I'm working on is to find and set up the integral whose value is the area of the surface obtained by rotating the curve about the x-axis, then another integral to find the surface area by rotating about the y-axis. I do not need to evaluate these integrals, just set them up. (I'm sorry I'm not using prper variable and notation signs in some parts, i'm worried about them not showing up correctly.) r = 1 + sin(4*Θ) where 0<= Θ <= 2pi I understand that I can find surface area of parametric equations using S = ʃ 2(pi)y sqrt([dx/dt]² + [dy/dt]²) dt (a->b) I'm also familiar with: x = r cos(Θ) y = r sin(Θ) r = sqrt(x² + y²) Θ = tan(y/x) And lastly, with all my efforts, basically all I did was write a bunch of stuff down and hope something jumped out at me. I drew a triangle and labeled it...(you can laugh at my attempt to draw it, you can also tell where theta is supposed to go) . |\ y | \ r = 1 + sin(4Θ) = sqrt(x² + y²) | \ ----` x and so sin(Θ) = y / (1 + sin(4Θ)) and sin(Θ) = y / (sqrt(x² + y²)) 1 + sin(4Θ) = sqrt(x² + y²) but it turns out I don't really know what I'm doing, I have no direction. Any help is greatly appreciated, thanks a lot!