Surface current of superconducting sphere in magnetic field

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The discussion focuses on the behavior of surface currents in a superconducting sphere placed in a magnetic field, emphasizing the continuity of magnetic field components. It highlights that the magnetic field inside a superconductor is zero, leading to a surface current confined to the sphere's surface. The derived equation shows the relationship between the surface current density and the external magnetic field, resulting in a specific expression for the current. An additional note suggests that a factor of 1/3 may be relevant due to the spherical geometry. The conversation concludes with equations relating magnetization and magnetic fields in the context of the discussed model.
Jan05
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Homework Statement
Suppose a sphere of superconductiong material is placed in a uniform magnetic field ##\mathbf{B} = B \, \hat{\mathbf{z}}##. What is the induced surface current distribution?
Relevant Equations
##\mathbf{B}_{above} - \mathbf{B}_{below} = \mu_0 (\mathbf{K} \times \hat{\mathbf{n}} )##
My idea was to use the continuity of parallel components of the magnetic field and the spherical coordinate system. Because the magnetic field in a superconducting material is 0 and the current is completely confined to the surface, there only is a ##\mathbf{B}_{above}## component. The equation then reduces to ##\mathbf{K} \times \hat{\mathbf{r}} = B / \mu_0 \, \hat{\mathbf{z}} ##. Then evaluating components and using ##\hat{\mathbf{z}} = \cos \theta \, \hat{\mathbf{r}} - \sin \theta \,\hat{\boldsymbol{\theta}}## we obtain ##K_\varphi \, \hat{\boldsymbol{\theta}} = B / \mu_0 \sin \theta \, \hat{\boldsymbol{\theta}}##. So ##\mathbf{K} = B / \mu_0 \sin \theta \, \hat{\boldsymbol{\varphi}}##.
 
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Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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