Surface Tension of needle on water

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Homework Help Overview

The discussion revolves around the concept of surface tension and its ability to support a needle placed on water. The problem involves calculating the maximum mass of a needle based on its length and the surface tension of water.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of forces involved, with one questioning whether they accounted for the full force necessary to support the needle. There is an exploration of the relationship between the needle's mass and the surface tension.

Discussion Status

Some participants are clarifying their understanding of the forces at play, with one suggesting that the original calculation may have omitted necessary components. There is an acknowledgment of the need to consider specific angles in the context of maximum weight.

Contextual Notes

Participants note the importance of using the correct formula and understanding the implications of surface tension in this scenario. There is a reminder about adhering to forum guidelines regarding homework submissions.

Aleisha
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I attempted the question but it was wrong... I don't understand where i went wrong my working seems logical, can someone please help.

When a needle is gently placed on the surface of still water (γ = 0.0730 N.m-1) it can be supported by surface tension if the mass of the needle is small enough.
Calculate the maximum mass of a needle that is 4.85 cm long that can be supported by the water. Take the acceleration due to gravity to be 9.80 m/s/s.
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Aleisha said:
I attempted the question but it was wrong... I don't understand where i went wrong my working seems logical, can someone please help.

When a needle is gently placed on the surface of still water (γ = 0.0730 N.m-1) it can be supported by surface tension if the mass of the needle is small enough.
Calculate the maximum mass of a needle that is 4.85 cm long that can be supported by the water. Take the acceleration due to gravity to be 9.80 m/s/s.View attachment 224645 View attachment 224646
You only included half the force.

P.S., Please use the Homework Template in the future.
 
So all I have to do is double my answer to get the full force?
 
Aleisha said:
So all I have to do is double my answer to get the full force?
Yes. You also have to understand that, at the maximum weight, ##\theta=0##.
 
I understand that now it makes sense, thank you!
 

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