Surjective, injective and predicate

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To determine if a function is surjective, one must show that for every element in the codomain, there exists an element in the domain that maps to it. For injectivity, the requirement is that if two elements in the domain map to the same element in the codomain, they must be identical. The discussion also touches on the concept of predicates as characteristic functions, though there is some confusion regarding the term "predicate." Additionally, participants seek to express the non-surjectivity and non-injectivity of functions using quantifiers and logical symbols. The conversation highlights the importance of understanding definitions and exploring examples, particularly in the context of combining functions.
reven
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Homework Statement



How do I check if my function is surjective?

How do I check if my function is injective?

Suppose my function is a predicate and hence characteristic function of some set. How do I determine such a set?

Homework Equations



Does anyone know to write "The function f: A->B is not surjective? and The function f:A-> B is not injective?" in SYMBOLS using quantifiers and operators.

The Attempt at a Solution



If I have two finite sets, and a function between them. I can compute the value of the function at each point of its domain, I can count and compare sets elements, but I don't know how to do anything else.
I need detailed, explicit instructions for answering the questions IN WORDS. Can anyone help me to solve this problem.

Cheers mate
 
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reven said:

Homework Statement



How do I check if my function is surjective?

How do I check if my function is injective?
By showing that the definitions of "surjective" and "injective" hold, of course. For example, to show that a function, f, from A to B, is surjective, you must show that, if y is any member of B, then there exist x in A so that f(x)= y. To show that a function, f, from A to B, is injective, you must show that if f(x1)= y and f(x2)= y, where x1 and x2 are members of A and y is a member of B, then x1= x2.

Suppose my function is a predicate and hence characteristic function of some set. How do I determine such a set?
Sorry, I don't recognize the term "predicate" as applied to functions.

Homework Equations



Does anyone know to write "The function f: A->B is not surjective? and The function f:A-> B is not injective?" in SYMBOLS using quantifiers and operators.
I would say that "f is not surjective" means "There exist y in B such that, for all x in X, it is not true that f(x)= y" and "f is not injective" means "for all y in B, if there exist x1 in X such that f(x1)= y and there exist x2 in X such that f(x2)= y, then x1= x2."

The Attempt at a Solution



If I have two finite sets, and a function between them. I can compute the value of the function at each point of its domain, I can count and compare sets elements, but I don't know how to do anything else.
I need detailed, explicit instructions for answering the questions IN WORDS. Can anyone help me to solve this problem.

Cheers mate
You need to know the DEFINITIONS of "injective" and "surjective"!
 
I was wondering, if f: R -> R is surjective and g: R -> R is surjective, then is f + g also surjective? Intuitively the answer seems to be yes, and I can't think of any counterexamples. Perhaps I'm not thinking hard enough.
 
snipez90 said:
I was wondering, if f: R -> R is surjective and g: R -> R is surjective, then is f + g also surjective? Intuitively the answer seems to be yes, and I can't think of any counterexamples. Perhaps I'm not thinking hard enough.

f(x)=x is surjective (and injective), g(x)=-x is also surjective (and injective), what is the sum of f and g?
 
Ah, okay, thanks. These questions come up so often in my theoretical calc class and they often amount to using the additive and multiplicative inverses for counter examples. I need to keep that in mind.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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