Surjectivity and linear maps question

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Homework Help Overview

The discussion revolves around the properties of linear maps, specifically focusing on the surjectivity of a linear map T from F^4 to F^2, given a specific kernel condition.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the dimensions of the kernel, image, and domain to determine surjectivity. Questions arise about the implications of the dimensions involved.

Discussion Status

Participants are actively discussing the dimensions of the kernel and image, with some suggesting that the dimensions indicate surjectivity. However, there is a clarification needed regarding the interpretation of dimensions in relation to vector spaces.

Contextual Notes

There is an ongoing examination of the definitions and properties of vector spaces and linear maps, particularly concerning the kernel and image dimensions. Some participants express confusion over the terminology used in the context of dimensions.

dyanmcc
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In my head this proof seems obvious, but I am unable to write it rigorously. :cry: Any help would be appreciated!

Prove that it T is a linear map from F^4 to F^2 such that

kernel T ={(x1, x2, x3, x4) belonging to F^4 | x1 = 5x2 and x3 = 7x4}, then T is surjective.
 
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What's the dimension of the image? (think in terms of the dimension of the domain and the dimension of the kernel)
 
the dimension of the kernel is two, the dimension of the range is two

so F^2 equals dim range and therefore is surjective?
 
dimension of kernel equal 2. Dimension of range equals 2.

dimension of domain equals 4. Since dim range = 2 and F^2 is the whole space of the range, then it is surjective?
 
dyanmcc said:
F^2 equals dim range and therefore is surjective?

F^2 is a vector space, so it can't equal a dimension.

The image is a 2-d subspace of a 2-d space, so it is all of it.
 

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