Suspending a Charged Droplet: Electric Field E Found by Millikan

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SUMMARY

The discussion centers on calculating the electric field (E) required to suspend a charged droplet in a gravitational field (g). The relevant equation derived is E = ((ρ g)/q) (4/3) ∏ R³, where ρ is the effective mass density, R is the radius of the droplet, and q is the total charge. This method is validated by confirming that the gravitational force equals the electric force acting on the droplet. Millikan's experiments established that droplets carry integer multiples of the elementary charge, e = -1.6 x 10^-19 coulombs.

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Homework Statement



A spherical droplet of radius R and effective mass density ρ. carries a total charge q in a gravity field g. What electric field E iz, will suspend the charged droplet? Millikan found by this method that all droplets carried integer multiples ofnegative charge e= -1.6 x 10-coul.

Homework Equations



F=ma

The Attempt at a Solution



I would like to confirm if my attempt is okay or not. Please can you give explanation based on whatever method it is required to be solved in.

q E = ρ g (4/3) ∏ R3

E = ((ρ g)/q) (4/3) ∏ R3
 
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4real4sure said:

Homework Statement



A spherical droplet of radius R and effective mass density ρ. carries a total charge q in a gravity field g. What electric field E iz, will suspend the charged droplet? Millikan found by this method that all droplets carried integer multiples ofnegative charge e= -1.6 x 10-coul.

Homework Equations



F=ma

The Attempt at a Solution



I would like to confirm if my attempt is okay or not. Please can you give explanation based on whatever method it is required to be solved in.

q E = ρ g (4/3) ∏ R3

E = ((ρ g)/q) (4/3) ∏ R3

It makes sense to me. You equated the gravitational force to the electric force (in magnitude). You computed the mass by multiplying the density by the volume. I don't see any problems.
 

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