SUVAT equations + two balls dropped at different times

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SUMMARY

The discussion focuses on the application of SUVAT equations to analyze the motion of two balls dropped from the same height at different times. The first ball is dropped at time t, while the second ball is dropped one second later, leading to confusion regarding the correct time variable to use. The correct interpretation is that for the second ball, the time should be represented as t2 = t1 - 1, where t1 is the time for the first ball and t0 is the time difference between the two drops. This clarification emphasizes the need to account for the time offset when applying SUVAT equations to multiple objects in motion.

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trew
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two balls dropped
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suvat
I'm continuing to struggle when it comes to objects that are dropped at different times.

At height h, a ball is dropped at rest.

Also at height h, another ball is dropped one second later.

For the first ball, time=t.

For the second ball, time=t+1...but this is wrong? The answers show it should be: t-1. How?

If I drop ball right now, then the time is t, and if I drop a second ball one second later, then isn't the time t+1?
 
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The SUVAT equations assume that t = 0 when motion starts. Imagine two separate clocks, 1 and 2. Each clock starts when its corresponding mass starts its motion. Write the SUVAT equations as usual using t1 and t2. The latter clock 2 will be behind clock 1 by t0, the time interval between the onset of the two motions. Therefore t1 = t2 + t0 because t1 is a greater number than t2.
 

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