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Swimmer's velocity relative to the shore (vectors)

  1. Aug 31, 2012 #1
    1. The problem statement, all variables and given/known data
    A swimmer is training in a river. The current flows at 1.33 metres per second and the swimmer's speed is 2.86 metres per second relative to the water. What is the swimmer's speed relative to the shore when swimming upstream? What about downstream?

    2. Relevant equations

    Pythagoras.

    3. The attempt at a solution

    Here's my problem. Because we're looking at vectors, I would normally do the vector sum of both the velocities and use Pythagoras, as both given vectors are perpendicular.


    Vcurrent = 1.33 m/s
    Vswimmer relative to water = 2.86 m/s

    So the resultant vector would be: [itex]\sqrt{}[/itex](1.332 + 2.862)

    Giving 3.15 m/s, however this is wrong, as the answer given is 1.53 m/s upstream.

    I'm puzzled as to how this answer was reached.
     
  2. jcsd
  3. Aug 31, 2012 #2
    The swimmer is not swimming across the river.
    He is swimming against the current. That how normally swimmers trainned.
    Now imagine you running in direction to the east at a speed 1.33 metres per second on a train with 1.33 metres per second speed heading west.
    To the man on the platform seeing you not moving, but with respect of the train you are running at 1.33 metres per second in easterly direction.
     
  4. Aug 31, 2012 #3

    TSny

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    Homework Helper
    Gold Member

    Hi, ulfy01.

    Note that "swimming upstream" means swimming in a direction opposite to the current, not perpendicular to the current. So, there is no right triangle here.

    [oops: I'm a bit late here, sorry.]
     
  5. Aug 31, 2012 #4
    I just realized this and made a fool of myself, really. Way to overthink a problem and not read it properly. I'll go hide in a corner now. Thanks azizlwl!
     
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