Symmetric Matrix Transpose: ABC^T ≠ CBA?

  • Thread starter Thread starter Ara macao
  • Start date Start date
  • Tags Tags
    Matrix Transpose
Click For Summary
SUMMARY

The discussion centers on the transpose of the product of three symmetric matrices A, B, and C, specifically questioning why (ABC)^T does not equal CBA. It is established that while (ABC)^T equals (C^T)(B^T)(A^T), the equality does not hold as C^T = C, B^T = B, and A^T = A for symmetric matrices. The consensus is that the solutions manual to Gilbert Strang's Linear Algebra incorrectly states that (ABC)^T equals CBA when it does not.

PREREQUISITES
  • Understanding of matrix operations, specifically transposition.
  • Familiarity with symmetric matrices and their properties.
  • Knowledge of linear algebra concepts as presented in Gilbert Strang's Linear Algebra.
  • Ability to interpret mathematical notation and proofs.
NEXT STEPS
  • Review the properties of symmetric matrices in linear algebra.
  • Study the rules of matrix transposition and multiplication.
  • Examine examples of matrix products and their transposes.
  • Consult Gilbert Strang's Linear Algebra for clarification on matrix properties.
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking to clarify concepts related to symmetric matrices and their transposes.

Ara macao
Messages
26
Reaction score
0
(ABC)^T, A,B,C are all symmetric, then why isn't (ABC)^T = CBA? If you consider that (ABC)^T = (C^T)(B^T)(A^T) and in symmetrix cases, then C^T = C and so on...?

(Latex edit by HallsofIvy)
 
Last edited by a moderator:
Physics news on Phys.org
Who says that (ABC)^T is not CBA when all three are symmetric?
 
The solutions manual to Gilbert Strang Linear Algebra...
 
Right, why don't you post the full question and the full answer from this book? I mean, is the question:

Q. if A,B, and C are symmetric does (ABC)^T = CBA?
A. No.
 
Right, why don't you post the full question and the full answer from this book? I mean, is the question:

Q. if A,B, and C are symmetric does (ABC)^T = CBA?
A. No.
 
Yes, that is the case
 
Then the asnwer book is wrong, if that is the precise statement of the question.
 
ABC \neqCBA
 
Last edited:
And no one is claiming that they are equal.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
Replies
2
Views
1K
Replies
5
Views
2K
Replies
2
Views
974
Replies
10
Views
8K
Replies
6
Views
2K
Replies
8
Views
3K
Replies
4
Views
2K
Replies
6
Views
1K
Replies
1
Views
1K