Synthesis reaction: turn 4-octyne into butanal

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Lo.Lee.Ta.
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Reaction scheme: a cis-alkene with two propyl groups, labelled from (a), is treated with 1. O3 and 2. Zn, CH3CO2H to give butanal, CH3CH2CH2CHO.


I know that first we have to add H2 and a Lindlar catalyst in order to produce what is the reactant.
I thought adding O3 would be an ozonolysis reaction.
An ozonolysis reaction should yield this:

Reaction scheme: an alkene with substituents R1, R2 on one carbon and R3, R4 on the other, treated with O3, gives two carbonyl compounds, R1R2C=O and R3R4C=O.


I don't know why they added the Zn and CH3CO2H, though.

What does this even do in the reaction?

Thanks for your help! :)
 
What is the structure of the first-formed product of the double bond with ozone and what is the mechanism of the reaction?