System equations - unique / no / infinite solution

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The discussion centers on determining the conditions under which a system of linear equations has unique, no, or infinite solutions. Specifically, the equations presented are x + (alpha)y = 3 and 2x + y = 3. It is established that when alpha = 1, the system has a unique solution. To find values of alpha that yield no solutions, one must analyze the determinant of the coefficient matrix. A determinant of 0 indicates a singular matrix, which can lead to either no solutions or infinitely many solutions, depending on the constants involved.

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For example,

x + (alpha)y = 3
2x + y = 3
if alpha = 1, there is an unqiue solution.

then what value(s) of alpha will make the system returns no solution?

and what can we do to make this system infinite solution (if we only change the value of [3 3])

I don't know how to determine whether a system has unique / no / or infinite solution.

Thanks for any help.
 
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Try writing it as a matrix and row-reducing.
 
Put the coefficients into a 2x2 matrix.

If the determinant is 0 then the matrix is singular. A singular matrix can either have 0 solutions or infinitely many solutions.
 

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