Suppose we have a system of 2 equations in 2 unknowns x,y:(adsbygoogle = window.adsbygoogle || []).push({});

a_{1}x+b_{1}y=c_{1}

a_{2}x+b_{2}y=c_{2}

If the determinant of

[a1 b1

a2 b2]

is nonzero, then the solution to the system exists and is unique. [I am OK with this]

If the determinant of

[a1 b1

a2 b2]

is zero,

this does not distinguish between the cases of no solution and infinitely many solutions.

To gain some insight, we need to further check the determinatnts of

[a1 c1

a2 c2]

and

[b1 c1

b2 c2]

If both determinants are zero, then the system has infinitely many soltuions.

If at least one of the two determinants are nonzero, then the system has no solution.

===================================

Is the bolded part correct or not? I don't see why it is true. How can we prove it?

Thanks for any help!

**Physics Forums - The Fusion of Science and Community**

# System of linear equations-unique, infinitely many, or no solutions

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: System of linear equations-unique, infinitely many, or no solutions

Loading...

**Physics Forums - The Fusion of Science and Community**