System of two equations with fractions

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Homework Help Overview

The discussion revolves around a system of two equations involving fractions. Participants are attempting to simplify and solve the equations, which are presented in a specific format. There is uncertainty regarding the correctness of the equations and their solutions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are discussing simplification attempts and expressing confusion about the correctness of the equations. There are questions about whether the equations have been stated correctly and concerns about the arithmetic involved.

Discussion Status

Some participants have provided guidance on solving simultaneous equations and have suggested checking arithmetic. There is a recognition of potential discrepancies in the equations and their solutions, with multiple interpretations being explored.

Contextual Notes

There are indications of possible errors in the problem setup, as one participant questions the validity of the second equation based on the provided answers. Additionally, there is mention of differing results from software calculations, which adds to the uncertainty in the discussion.

Hivoyer
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Homework Statement



These are the two equations:

(7 + x)/5 - (2x - y)/4 - 3y = -5
(5y - 7)/2 - (4x - 3)/6 - 18 = -5x

Homework Equations





The Attempt at a Solution



When I try to simplify it, I end up with:

6x + 55y = 128
34x + 15y = 129

I'm not sure where to go with this, I think I should have gone a different route instead of just trying to simplify the equations.Does anyone know where I might have gone wrong?
By the way, in the answers of the book it says that X is 3 and Y is 2, however I must find them by solving the problem, but I am stuck.Any help would be appreciated.
 
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Hivoyer said:
(7 + x)/5 - (2x - y)/4 - 3y = -5
(5y - 7)/2 - (4x - 3)/6 - 18 = -5x
:
the book it says that X is 3 and Y is 2,
Are you sure you've stated the problem correctly? The second one is perhaps = -6x on the right?
6x + 55y = 128
34x + 15y = 129
Have you not been shown how to solve simultaneous equations? It's very easy. One way is to write one of the equations in the form y = (some expression with x and constants but no y's), then use that to replace y in the other equation.
 
Yeah thanks, but it seems like the problem is wrong, the second equation doesn't add up with the answer they've given, even when I calculate it with software.
 
Hivoyer said:

Homework Statement



These are the two equations:

(7 + x)/5 - (2x - y)/4 - 3y = -5
(5y - 7)/2 - (4x - 3)/6 - 18 = -5x

Homework Equations





The Attempt at a Solution



When I try to simplify it, I end up with:

6x + 55y = 128
34x + 15y = 129

I'm not sure where to go with this, I think I should have gone a different route instead of just trying to simplify the equations.Does anyone know where I might have gone wrong?
By the way, in the answers of the book it says that X is 3 and Y is 2, however I must find them by solving the problem, but I am stuck.Any help would be appreciated.

The solution of your two equations (exactly as written) is x = 501/134, y = 643/335. Are you sure you wrote the correct equations?

BTW: when I (or, actually, Maple 14) simplify your equations I get
[tex]6x + 55y = 128\\<br /> 26x + 15y = 126[/tex]
and these also give the values of x and y as stated above.
 
Check your arithmetic on both equations.
 

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