T = sqrt(m/k)^(1/2pi), solve for k

[TyErd]

how do you make k the subject in the time period of oscillation formula:

T=sqrt(m/k)^(1/2pi)

 

[Mark44]

how do you make k the subject in the time period of oscillation formula:

T=sqrt(m/k)^(1/2pi)

Your formula is ambiguous. This is what it looks like to me.
$$T = \left(\sqrt{\frac{m}{k}}\right)^{\frac{1}{2\pi}$$

But that doesn't look like anything I've seen.

 

[TyErd]

oh sorry there's no sqrt, my bad its suppose to be m/k^1/2pi

 

[Mark44]

And is the exponent 1/(2pi) or (1/2)pi? IOW, is pi in the numerator or the denominator?

 

[TyErd]

denominator it is 1/(2pi), like the formula you wrote without the sqrt sign.

 

[Mark44]

$$T = \left(\frac{m}{k}\right)^{\frac{1}{2\pi}$$
If it's this one, raise each side to the power 2pi, then take the reciprocal of both sides. That should get you close to being able to solve for k.

 

[TyErd]

so it is k=m/(T^2pi)?

 

[Mark44]

so it is k=m/(T^2pi)?

Right

 

[gabbagabbahey]

oh sorry there's no sqrt, my bad its suppose to be m/k^1/2pi

Is this equation supposed to represent the period of oscillation of a Harmonic oscillator with spring constant $k$ and mass $m$? If so, it is incorrect.

The actual period is $$T=\frac{1}{2\pi}\sqrt{\frac{m}{k}}$$, which is quite different from the formula you've written.