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Tabular and Recursive Integration By Parts don't agree for the

Integral of [Ln x]^2 dx

Using Tabular Integration By Parts …………

....................................................1

[ Ln x ]^2 ..................................... x

2 (Ln x)( 1/x )................................x^2 / 2

2 (1/x) (1/x) + 2Ln x (–1/x^2)............x^3 / 6

I get ..............

x(Ln x)^2 – x Ln x + (1/3) x (1 – Ln x) = x(Ln x)^2 – (4/3)x Ln x + (1/3) x

But WolframAlpha gives ..

x(Ln x)^2 – 2x Ln x + 2x)

Thanks for any suggestions.

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# Tabular and Recursive IBP don't agree

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