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Tadpole graph & normal ordering

  1. Nov 25, 2007 #1
    It is said that so called tadpole graph gets eliminated from perturbation expansion if the normal-ordered interaction is adopted. How can it be proved? Can anybody provide some links or any other references about this problems?

    [tex]L_{int}=-e:\bar{\psi}\gamma_{\mu}\psi A^{\mu}:[/tex]
     
    Last edited: Nov 25, 2007
  2. jcsd
  3. Nov 25, 2007 #2
    Here is attachement with this graph
     

    Attached Files:

  4. Nov 25, 2007 #3
    ...and this also should remove the mass shift I suppose.
     
  5. Nov 26, 2007 #4

    blechman

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    See Peskin and Schroder, Chapter 4.

    You can see right away that (at least in QED) tadpoles for the photon must vanish, since QED has a charge-conjugation symmetry in which the photon field is odd, so the one-point function for the photon must vanish. You can also see that the diagram you included vanishes since the loop integral explicitly vanishes:

    [tex]\int d^4k\frac{{\rm Tr}[\gamma^\mu(k\!\!\!\slash+m)]}{k^2-m^2}= \int d^4k\frac{4k^\mu+0}{k^2-m^2}=0[/tex]

    These two statements are, of course, related.
     
  6. May 13, 2009 #5
    How do you know that it is zero by direct computation?
     
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