Take the anti derivative of (X^2)/sqrt(1-x)soln'let u=1-x

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SUMMARY

The discussion focuses on finding the anti-derivative of the function (X^2)/sqrt(1-x) using the substitution method with u=1-x. The initial attempt involved substituting x^2 with (1-u)^2, leading to an incorrect formulation. The correct approach is to express the integral as -∫(1-u)^2/√u du, which simplifies to -∫u^(-1/2)(1-2u+u^2) du. This method allows for proper distribution and integration of the terms.

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johnnyboy2005
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take the anti derivative of (X^2)/sqrt(1-x)

soln'... let u=1-x... then -du=dx and x^2 = (1-u)^2 (sub back in)...

this gives me -2*u^(1/2)*(15-10*u+3*u^2) /15... (sorry for lack of proper terms)


anyway, this turns out to be wrong...where did i go wrong here?
 
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Try this:

\int \frac{x^2}{\sqrt{1-x}}dx = -\int \frac{(1-u)^2}{\sqrt{u}}du = -\int u^{-\frac{1}{2}}(1-2u+u^2) du

then distribute the u^{-\frac{1}{2}} term over the quadratic and integrate
 
yeah...that's what i was getting but it was in a different form. Thanks a lot !1
 

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