Take the derivative of rational expression

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Homework Help Overview

The discussion revolves around finding the first derivative of the rational expression f(x) = \frac{x}{x-1} + \frac{x+1}{3x}. Participants are exploring the implications of taking derivatives of individual terms versus simplifying the expression first.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions why they cannot simply take the derivative of each term separately and add the results, expressing confusion over arriving at different answers compared to the expected result from combining and simplifying first.

Discussion Status

Some participants suggest that it is indeed possible to take the derivatives of the individual terms and sum them. There is a suggestion to check for arithmetic mistakes in the original poster's calculations, indicating that guidance has been offered without reaching a consensus on the correct approach.

Contextual Notes

The original poster indicates uncertainty about their algebraic manipulation and expresses a willingness to rework their solution, suggesting that they are operating under typical homework constraints regarding the derivation process.

rambo5330
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Homework Statement




f(x) = [tex]\frac{x}{x-1}[/tex] + [tex]\frac{x+1}{3x}[/tex]

Homework Statement


need to take the first derivative of this expression...
I can do it but I am curious as too why i cannot take the derivative of

[tex]\frac{x}{x-1}[/tex] and then just add it to the derivative of [tex]\frac{x+1}{3x}[/tex]


rather than finding a common denominator off the bat and simplifying to one expression then taking derivative of that...

I get two separate answers? the combining and simplifying method arrives at the answer in the text...
 
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You can take the derivative of each and add them up. You are probably doing some arithmetic mistake.
 
rambo5330 said:

Homework Statement

f(x) = [tex]\frac{x}{x-1}[/tex] + [tex]\frac{x+1}{3x}[/tex]

Homework Statement


need to take the first derivative of this expression...
I can do it but I am curious as too why i cannot take the derivative of

[tex]\frac{x}{x-1}[/tex] and then just add it to the derivative of [tex]\frac{x+1}{3x}[/tex]rather than finding a common denominator off the bat and simplifying to one expression then taking derivative of that...

I get two separate answers? the combining and simplifying method arrives at the answer in the text...

You can take the derievatives of each individual term and sum them.

My guess is that you made an error somewhere. Check your solution again or post it here. :)

EDIT

Inferior89 beat me to it :)
 
thanks I figured I could based on the rules... but I cannot see where I am making the mistake algebraically.. I'll rework again and post if i do not see the error of my ways
 

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