Taking the derivative of displacement

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The discussion focuses on the derivation of the equation v = v0 + at from the displacement equation y = y0 + v0t + 1/2 at^2. It clarifies that taking the derivative of y with respect to time (dy/dt) leads to the velocity equation. The constant term y0 does not change with time, resulting in its derivative being zero. The participants explore the differentiation process, emphasizing the role of constants and initial velocity in the equations. Understanding these relationships is crucial for solving kinematic problems in physics.
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Homework Statement



how does y= y0 + v0t + 1/2 at2

become v = v0 + at ?

know v= dy/dt

Homework Equations




The Attempt at a Solution



dy/dt = dyo/dt + v0 + at

v= vo + vo +at
v= 2vo + at
 
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cs23 said:

Homework Statement



how does y= y0 + v0t + 1/2 at2

become v = v0 + at ?

know v= dy/dt

Homework Equations




The Attempt at a Solution



dy/dt = dyo/dt + v0 + at

y0 here is a constant and does not depend on time. So d/dt(y0) = 0.
 

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