- #1

- 350

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Multiplying dt on both sides and integrating we have

##\int_{x_f}^{x_i} dx = \int_{0}^{v_i t} dx_i + \int_{0}^{at} dvt##

so ##x_f - x_i = v_it + at^2##, which is not right

Where did I go wrong?

I understand that if we substitute a for ##\frac{d^2x}{dt^2}##, integrating atdt = 0.5at, but what if we derived the equation for displacement by multiplying by dt?