Taking the derivative of displacement

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SUMMARY

The discussion focuses on the derivation of the equation for velocity from the displacement equation \(y = y_0 + v_0t + \frac{1}{2} at^2\). The transformation to the velocity equation \(v = v_0 + at\) is achieved by taking the derivative of the displacement with respect to time, where \(v\) is defined as \(dy/dt\). The constant \(y_0\) does not contribute to the derivative, simplifying the equation to \(v = v_0 + at\).

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  • Knowledge of the concepts of displacement, velocity, and acceleration
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cs23
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Homework Statement



how does y= y0 + v0t + 1/2 at2

become v = v0 + at ?

know v= dy/dt

Homework Equations




The Attempt at a Solution



dy/dt = dyo/dt + v0 + at

v= vo + vo +at
v= 2vo + at
 
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cs23 said:

Homework Statement



how does y= y0 + v0t + 1/2 at2

become v = v0 + at ?

know v= dy/dt

Homework Equations




The Attempt at a Solution



dy/dt = dyo/dt + v0 + at

y0 here is a constant and does not depend on time. So d/dt(y0) = 0.
 

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