Taking the Second Derivative w/ the Quotient Rule: What if Numerator = 0?

Click For Summary

Discussion Overview

The discussion revolves around the process of taking the second derivative using the quotient rule, specifically addressing a scenario where the numerator of the second derivative calculation results in zero. The conversation includes aspects of mathematical reasoning and clarification of derivative calculations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant inquires about the procedure for taking the second derivative using the quotient rule, noting that the numerator becomes zero.
  • Another participant requests the exact working of the calculations to better understand the issue.
  • A participant provides a specific function, s(t) = t^2 - 2/t + 1, and mentions a potential calculation error leading to a zero numerator in the acceleration function a(t).
  • Another participant corrects the function to s(t) = (t^2 - 2)/(t + 1) and provides the derived expressions for velocity v(t) and acceleration a(t).
  • One participant emphasizes the importance of differentiating the velocity function v(t) to find acceleration a(t) before substituting a specific time value.
  • A later reply indicates understanding after receiving clarification on the process.

Areas of Agreement / Disagreement

Participants appear to agree on the need to differentiate the velocity function to obtain acceleration, but there is no consensus on the initial function or the specific calculations leading to the zero numerator.

Contextual Notes

There are potential limitations in the clarity of the function definitions and the steps taken in the differentiation process, which may affect the understanding of the problem.

mathmann
Messages
37
Reaction score
0
Just wondering how you take the second derivative when using the quotient rule. After using the quotient rule to get my first derivative, I tried again and the numerator ended up as 0.
 
Physics news on Phys.org
Can you show us your exact working?
 
s(t) = t^2 - 2/t + 1, is the object speeing up at 4s?
v(t) = 1.04, a(t) the numerator ended up as a 0. Perhaps I made a calculating error but I went over it a couple times.
 
You mean s(t) = (t^2 - 2)/(t + 1) right?

Then v(t) = (t^2 + 2t + 2)/(t+1)^2

and a(t) = - 2/ (t+1)^3
 
When you evaluate v(t) at some fixed t you get the velocity at that point in time. You are not supposed to differentiate that particular velocity to get the acceleration at that time. You need to work out a(t) first by differentiating the function v(t) before substituting in your fixed t.
 
I understand now.. thanks for the help.
 
No problem :smile:
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
941
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K