Tangential velocity needed for Wall of Death ride with given friction

[am08]

The Wall of Death in an amusement park is comprised of a vertical cylinder that can spin around the vertical axis. Riders stand against the wall of the spinning cylinder and the floor falls away leaving the riders held up by friction. The radius of the cylinder is 3.9 m and the coefficient of static friction between the rider and the wall is 0.35. Find the tangential velocity of the spinning wall necessary so that the riders do not slip down the wall.

Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How do I apply that to find the tangential velocity?

 

[Shooting Star]

Centripetal Acc = (.35*9.8) = 3.43 m/s^2

How did you get this??

Centripetal force is the normal reaction N. The frictional force F must be equal to weight. You should know the relationship between F and N when static friction is max. Now write the correct eqn for minimum tangential velocity.