The discussion revolves around finding the tangent plane to the surface defined by the equation z = ycos(x - y) at the point (2, 2, 2). The subject area includes calculus, specifically the application of partial derivatives in multivariable functions.
The discussion is ongoing, with some participants providing guidance on the need to apply the product rule for the partial derivative fy. There is acknowledgment of uncertainty regarding the initial attempts, but no consensus has been reached yet.
Participants express doubt about their calculations and the application of differentiation rules, indicating a potential misunderstanding of the product rule in the context of the problem.
Welcome to Physics Forums.day1ok said:Find the tanget plane using partial derivatives.
z=ycos(x-y), at point (2,2,2)attempted: fx(x,y)=ysin(x-y)*1
fx(2,2)=0
fy(x,y)=1*sin(x-y)*1
fx(2,2)=0
z-2=0(x-2)+0(x-2)
z=2 Incorrect