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Taylor series and quadratic approximation

  1. Mar 1, 2008 #1
    1. The problem statement, all variables and given/known data

    use an appropriate local quadratic approximation to approximate the square root of 36.03

    2. Relevant equations

    not sure

    3. The attempt at a solution

    missed a day of class
  2. jcsd
  3. Mar 1, 2008 #2


    User Avatar

    You need to rwwrite
    [tex] \sqrt{36+0.03} [/tex]
    in the form [tex] 6 \sqrt{1+\epsilon} [/tex] and then expand this to order epsilon squared. I will let you figure out what the value of epsilon is.
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