tnutty Messages 324 Reaction score 1 Thread starter Apr 6, 2009 #1 True/false The taylor series below converges for all x to e^-x n-infinity [tex]\sum[/tex] (-1)^(n-1) * 1/n * x^n n=1
True/false The taylor series below converges for all x to e^-x n-infinity [tex]\sum[/tex] (-1)^(n-1) * 1/n * x^n n=1
SNOOTCHIEBOOCHEE Messages 141 Reaction score 0 Apr 6, 2009 #2 well the series for e^x is Sum: x^n/n! I will assume you forgot to put the factorial in there. Cause then it is obviously falso So now (-1x)^n/n!= (-1)^n x^n/n! = e^-x So this is false, it converges to -e^-x my notaion is very sloppy, but you get the picture
well the series for e^x is Sum: x^n/n! I will assume you forgot to put the factorial in there. Cause then it is obviously falso So now (-1x)^n/n!= (-1)^n x^n/n! = e^-x So this is false, it converges to -e^-x my notaion is very sloppy, but you get the picture
tnutty Messages 324 Reaction score 1 Apr 6, 2009 #3 nope did not forgot the factorial. Why is it obviously false then.