Taylor Series Converges to e^-x for All x

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SUMMARY

The Taylor series given by the expression ∑ (-1)^(n-1) * 1/n * x^n does not converge to e^-x for all x. The correct series for e^x is ∑ x^n/n!, and when applying the negative exponent, the series should be ∑ (-1)^n * x^n/n!, which converges to e^-x. The initial assumption that the series converges to -e^-x is incorrect, as the factorial was not omitted.

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True/false The taylor series below converges for all x to e^-x

n-infinity
[tex]\sum[/tex] (-1)^(n-1) * 1/n * x^n
n=1
 
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well the series for e^x is Sum: x^n/n!

I will assume you forgot to put the factorial in there. Cause then it is obviously falso

So now (-1x)^n/n!= (-1)^n x^n/n! = e^-x

So this is false, it converges to -e^-x

my notaion is very sloppy, but you get the picture
 
nope did not forgot the factorial. Why is it obviously false then.
 

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