Finding the Taylor Series of f(x) = x/(2+x)

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SUMMARY

The Taylor series for the function f(x) = x/(2 + x) can be expressed in terms of y = x + 1. By rewriting the function as F(y) = (y - 1)/(y + 1), users can apply their knowledge of Taylor series to derive the expansion. The transformation simplifies the function to F(y) = 1 - 2/(y + 1), which facilitates the series expansion. The general term can be determined through standard Taylor series techniques.

PREREQUISITES
  • Understanding of Taylor series expansions
  • Familiarity with algebraic manipulation of rational functions
  • Knowledge of series convergence criteria
  • Basic calculus concepts, particularly derivatives
NEXT STEPS
  • Study the derivation of Taylor series for various functions
  • Learn about convergence and radius of convergence for Taylor series
  • Explore the application of Taylor series in approximating functions
  • Investigate the use of symbolic computation tools like Mathematica for series expansions
USEFUL FOR

Students studying calculus, mathematicians interested in series expansions, and educators teaching Taylor series concepts.

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Homework Statement


Obtain the Taylor series in powers of x + 1 for f(x) = x/(2 + x), giving
the general term.


Homework Equations





The Attempt at a Solution



Wrote it out as x*(1/1-(-(x+1)).
 
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If
<br /> f(x)=\frac{x}{x+2}<br />
We are asked to write it as a series in y=x+1, so in terms of y, the function becomes:
<br /> F(y)=\frac{y-1}{y+1}<br />
Now use all your previous knowledge about Taylor series to find the expansion in terms of y
 
hmm.. confused
 
OK, write your function as the following:
<br /> f(x)=\frac{x}{x+2}=\frac{(x+1)-1}{(x+1)+1}<br />
Use all the previous knowledge you have to find the taylor series.
 
Or you could write:
<br /> f(x)=\frac{x}{x+2}=\frac{x+2-2}{x+2}=1-\frac{2}{x+2}=1-\frac{2}{(x+1)+1}<br />
If that makes it easier.
 

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