Temperature increase in water question

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SUMMARY

The discussion centers on calculating the temperature increase of 5kg of water when a 50kg aluminum block, dropped from a height, impacts the water at a velocity of 150 m/s. The kinetic energy (KE) of the block is calculated using the formula KE = 0.5 * m * v², resulting in 562,500 Joules. This energy is transferred to the water, leading to a temperature change calculated using the equation Q = mcΔt, yielding a temperature increase of 26.9°C.

PREREQUISITES
  • Understanding of kinetic energy (KE) calculations
  • Familiarity with the specific heat capacity of water (4,180 J/kg°C)
  • Knowledge of the heat transfer equation Q = mcΔt
  • Basic algebra for solving equations
NEXT STEPS
  • Review the principles of energy conservation in physics
  • Explore more complex heat transfer scenarios involving different materials
  • Learn about the effects of temperature changes on physical states of matter
  • Investigate the implications of kinetic energy in real-world applications
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Students studying physics, particularly those focusing on mechanics and thermodynamics, as well as educators looking for practical examples of energy transfer concepts.

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1. A 50kg alumium block is dropped from a large height and hits a container of water at 150m/s. Assuming all the kinetic energy of the falling block goes into heating the 5kg water, what is the temperature increase of the water.

Homework Equations


Q=mc(change of t)
KE=.5m(v^) maybe?[/B]

The Attempt at a Solution



.5(50)(150^)=562500 Jules
562500= 5(4180)(change of t)
change of t= 26.9[/B]
 
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