Temperature of water at different temperature mixed together

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SUMMARY

The final temperature of a mixture of 100g of water at 370K and 200g of water at 290K can be calculated using the principle of conservation of energy. The heat lost by the warm water equals the heat gained by the cool water, leading to the equation: m1*c*(T_initial1 - T_final) = m2*c*(T_final - T_initial2), where m represents mass, c is the specific heat capacity of water, and T represents temperature. By solving this equation, one can determine the final equilibrium temperature of the mixture.

PREREQUISITES
  • Understanding of specific heat capacity of water
  • Basic knowledge of thermodynamics principles
  • Ability to manipulate algebraic equations
  • Familiarity with temperature scales (Kelvin)
NEXT STEPS
  • Learn about the conservation of energy in thermodynamic systems
  • Study the specific heat capacity of various substances
  • Explore the concept of thermal equilibrium
  • Practice solving heat transfer problems using algebra
USEFUL FOR

Students in physics or chemistry, educators teaching thermodynamics, and anyone interested in understanding heat transfer and thermal equilibrium in mixtures.

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100g of water at 370K are mixed slowly with 200g of water at 290K. What is the final temperature?

Totally no clue where to start. Do I use the specific heat capacity of water? But what is the heat energy?
 
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Yes you use specific heat capacity.
The heat lost by the warm water is equal to the heat gained by the cool water.
The clue is that at the end they are both at the same temperature.
Write down the formula for heat gained by the cool water, then equate it to the heat lost by the hot water.
 
temperature is energy / degree of freedom

therefore temperature is proportional to energy
 

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