Tennis Ball Collision Homework Solution

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SUMMARY

The discussion focuses on solving a perfectly elastic collision problem involving a 0.060 kg tennis ball and a 0.090 kg ball. The initial speeds are 2.50 m/s and 1.00 m/s, respectively. After applying the conservation of momentum and the elastic collision equations, the final speeds are determined to be 1.40 m/s to the right for the second ball and 2.10 m/s to the left for the first ball. The solution confirms that momentum is conserved throughout the collision.

PREREQUISITES
  • Understanding of conservation of momentum
  • Knowledge of elastic collision equations
  • Familiarity with basic physics concepts such as mass and velocity
  • Ability to solve algebraic equations
NEXT STEPS
  • Review the principles of elastic collisions in physics
  • Study the conservation of momentum in multi-object systems
  • Practice solving similar collision problems using different masses and speeds
  • Explore the implications of inelastic collisions for comparison
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for practical examples of elastic collisions in action.

Of Mike and Men
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Homework Statement


A 0.060 kg tennis ball, moving with a speed of 2.50 m/s has a head on collision with a 0.090 kg ball initially moving toward it with a speed of 1.00 m/s. Assuming a perfectly elastic collision, what is the speed and direction of each ball after the collision?

Homework Equations


m1v1 + m2v2 = m1v1' +m2v2'

v1-v2 = v2' - v1'

The Attempt at a Solution



I drew my positive x-direction to the right. Thus, ball 1 is going to the right prior to the collision and ball 2 is going to the left prior to the collision.v1' = (m1v1 + m2v2 - m2v2') / m1

v1' = (0.06(2.5)-0.09-0.09v2')/(0.06)
v1' = (0.06 - 0.09v2')/0.06
v1' = -1.5v2'

v1-v2 = v2' - v1'
2.5+1 = 2.5v2'
v2' = 1.40
1.40 m/s to the right

v1' = v2' - v1 + v2
v1' = 1.4 - 2.5 - 1
v1' = -2.1
2.10 m/s to the left

Does this look correct?
 
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Of Mike and Men said:
Does this look correct?

You could check whether momentum is indeed conserved in your solution.
 
Duh. Thanks. :)
 

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