Solving Tension in Massless, Frictionless Pulley System

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SUMMARY

The discussion focuses on calculating the tension T in a massless, frictionless pulley system with two weights: m1 at 661 g and w2 at 5 N. The correct approach involves using free-body diagrams to analyze the forces acting on each mass. The user initially miscalculated tension by incorrectly assuming T equals the sum of weights. It is established that the tension in each segment of the rope may differ, necessitating a detailed examination of the system's dynamics.

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  • Understanding of Newton's laws of motion
  • Knowledge of free-body diagrams
  • Basic principles of tension in pulley systems
  • Ability to convert units (grams to kilograms)
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  • Study the principles of tension in non-equilibrium systems
  • Learn to draw and analyze free-body diagrams for complex systems
  • Explore the effects of mass and weight on tension in pulley systems
  • Review examples of massless and frictionless pulley problems in physics textbooks
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Students studying physics, particularly those focusing on mechanics and pulley systems, as well as educators seeking to clarify concepts related to tension and free-body diagrams.

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Homework Statement


What is the tension T? The pulley is massless and frictionless.
m1=661 g, w2=5 N, g=9.8 m/s2
Picture attached



Homework Equations


T=w1+w2 ??


The Attempt at a Solution


First of all, I converted 661 g into kg. Next I multiplied that by g. I added that value to the 5N and I thought that was the T which was wrong.
 

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If you draw a free-body diagram you don't have to think as hard IMO. See the attached.
 

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Where did you get the 2T' from?
 
I drew a free-body diagram for both masses. The tension T will not be the same as the tension in the other rope. Do the two free-body diagrams I drew make sense?
 

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