Tension Change When Spreading Scales: What Happens and Why?

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SUMMARY

The discussion focuses on the relationship between the tension in scales and their separation distance in a physics problem involving two scales and gravitational force. As the scales are spread farther apart, the tension in each scale increases due to the need to balance the gravitational force (Fg = mg) acting on the system. The tension remains equal in both scales, but the angles involved affect the tension's magnitude. Understanding the role of the x and y components is crucial for solving the problem accurately.

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  • Understanding of gravitational force (Fg = mg)
  • Knowledge of trigonometric functions, specifically sine
  • Familiarity with free body diagrams
  • Basic principles of static equilibrium
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  • Study the effects of angle changes on tension in static systems
  • Learn about free body diagram construction and analysis
  • Explore the relationship between tension and angle in physics
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Homework Statement



physicstension.jpg

Continue to spread the scales farther apart. What happens to the tension in each scale? Why? [Quick question: There are two scales, so would I have to draw two boxes?]

Homework Equations


Fg=mg
sin70degrees=FTy/FT ---> FTy/sin70degrees

The Attempt at a Solution

So, I understand that when the two angles are the same, then the sum of both FTen would equal to Fg. As the scales are moved further apart, then the tension of one scale would still be equivalent to the other. That must mean the tension increases as they move away, but as I thought before, they still equal to each other. I don't really understand what happens to the tension and why... I also don't quite understand the role of the x and y components besides solving for missing angles/sides and such.
 
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Hi mouasee, welcome to PF.
Please post the complete problem.
 

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