- #1

Sarah Lee

- 1

- 0

## Homework Statement

There is a tether ball swinging around in a uniform circle on a rope that is 1.90m long. Marcus hit the ball so hard that the string holding the ball made a 20.0 degree angle to the horizontal. What is the tension in the rope if the ball has a mass of 1.40 kg? Assume that the rope is not wrapping around pole so that the length of the rope doesn't change. What is the linear speed of the ball?

Show all Work

Answer=40.1N, 6.93m/s

## Homework Equations

F=ma=Ft-Fg

Ftx=fgcos

Fty=fgsin

## The Attempt at a Solution

F=ma=Ft-Fg

Ftx=Fgcos?

Fty=Fgsin20=1.40*9.8(sin20)=4.69

I tried Ft=fg/sin20 and got 40.1, searched it on google, but I don't understand why i did Ft=fg/sin20, nor how i get it.