Tension in Strings Holding Up Shelf

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The discussion revolves around a physics problem involving a 50.0 cm shelf supported by two vertical wires, with a total downward force of 83 N due to the shelf and a tool placed on it. The equilibrium condition requires that the upward forces equal the downward forces. To solve for the tensions in the wires, one can analyze the torques about the left support point, equating the torque produced by the shelf and tool's weight to the torque from the tension in the right wire. A miscalculation in the distance from the left wire was identified as a key error in the initial approach. The focus remains on applying the principles of static equilibrium to find the correct tensions in the supporting wires.
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1. A 50.0 cm, uniform, 57.0 N shelf is supported horizontally by two vertical wires attached to the sloping ceiling (the figure ). A very small 26.0 N tool is placed on the shelf midway between the points where the wires are attached to it.
http://session.masteringphysics.com/problemAsset/1260552/1/YF-11-23.jpg

2. All I know is that The downward force which is 83 N (26 N+ 57 N) and upward force must be equal to zero because this is an equilibrium problem.
3. I have tried to find the center of gravity:
x=(m1x1+m2x2)/(m1+m2)--> 185.2040Kgcm/8.469 Kg = 21.867 cm from the left, after this I am unsure how to proceed.
 
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ARL91 said:
1. A 50.0 cm, uniform, 57.0 N shelf is supported horizontally by two vertical wires attached to the sloping ceiling (the figure ). A very small 26.0 N tool is placed on the shelf midway between the points where the wires are attached to it.
http://session.masteringphysics.com/problemAsset/1260552/1/YF-11-23.jpg




2. All I know is that The downward force which is 83 N (26 N+ 57 N) and upward force must be equal to zero because this is an equilibrium problem.



3. I have tried to find the center of gravity:
x=(m1x1+m2x2)/(m1+m2)--> 185.2040Kgcm/8.469 Kg = 21.867 cm from the left, after this I am unsure how to proceed.

You can proceed by taking moments about the points where the shelf is supported.

Suppose you start with the leftmost support point. Assuming that all the mass of the shelf and tool are concentrated at their center of mass, what torque does this weight produce about the left hand suspension point? Then, if the torque caused by the tension in the right hand suspension wire must exactly counteract this (sum of the torques must be zero for a static system), what must the tension be?
 
Thank you so much! Turns out I was using the wrong distance from the left wire.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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