1. The problem statement, all variables and given/known data A 50.0 kg person takes a nap in a backyard hammock. Both ropes supporting the hammock are at an angle of 15° above the horizontal. Find the tension in the ropes. 2. Relevant equations T=mg, F=ma, T= (Tcos15°)+(Tsin15°) 3. The attempt at a solution What I did was I started with X and Y coordinates and I figured the coordinates in the X direction would cancel out to be 0 because in one X direction it is positive and the other is negative so the total tension would be the tension in the y direction multiplied by two. What I did was I got the total tension as ƩF= 2Tsin15° which is nowhere near the correct answer in the answer key. The correct answer is 948N which would be the cos of 15 degrees and not the sin. I don't understand how you know which one to us because if the ropes are 15 degrees above the horizontal I figured the x coordinates would cancel out.