(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 50.0 kg person takes a nap in a backyard hammock. Both ropes supporting the hammock are at an angle of 15° above the horizontal. Find the tension in the ropes.

2. Relevant equations

T=mg, F=ma, T= (Tcos15°)+(Tsin15°)

3. The attempt at a solution

What I did was I started with X and Y coordinates and I figured the coordinates in the X direction would cancel out to be 0 because in one X direction it is positive and the other is negative so the total tension would be the tension in the y direction multiplied by two. What I did was I got the total tension as ƩF= 2Tsin15° which is nowhere near the correct answer in the answer key. The correct answer is 948N which would be the cos of 15 degrees and not the sin. I don't understand how you know which one to us because if the ropes are 15 degrees above the horizontal I figured the x coordinates would cancel out.

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# Homework Help: Tension of ropes when laying on a hammock

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