Tension on the string is doing work

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In the discussion, participants explore whether the tension in a string does work on a ball swung in circular motion. It is clarified that while tension is present, it acts perpendicular to the ball's displacement, resulting in no work being done since work requires a component of force in the direction of displacement. The concept of work is defined as the dot product of force and displacement, emphasizing that if the angle between them is 90 degrees, the work done is zero. The mechanical energy of the system remains constant, indicating no energy loss despite the tension. Overall, the consensus is that tension does not perform work on the ball in this scenario.
BlueOwl
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Homework Statement



When someone ties a string to a ball and swings it in a circular motion is the string doing work on the ball?

Homework Equations





The Attempt at a Solution



Ok I am a little bit lost here it does seem that the tension on the string is doing work on the ball but again there is no change in kinetic energy(constant rotation) so could there be no work at all? I am totally lost here .
 
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BlueOwl said:

Homework Statement



When someone ties a string to a ball and swings it in a circular motion is the string doing work on the ball?

Homework Equations





The Attempt at a Solution



Ok I am a little bit lost here it does seem that the tension on the string is doing work on the ball but again there is no change in kinetic energy(constant rotation) so could there be no work at all? I am totally lost here .

Write down the expression for the work done by a force on an object (Hint: It is not "force times distance") and apply it to this situation.
 


The tension force of the string which coincide with the length of the string. It didn't make any difference of distance with the axis, so, it didn't loss any energy.
 


prob_solv said:
The tension force of the string which coincide with the length of the string. It didn't make any difference of distance with the axis, so, it didn't loss any energy.

In theory yes the mechanical energy of the system stays constant i.e. KE+PE=constant.

But does if work is said to be done when a force F moves it point of application through a displacement s in the direction of the force, would the string do work on the ball?
 


The tension force is perpendicular with the movement of s. You may not just multiply it without seeing the vector.
 


prob_solv, that's a dead give-away, I think you should edit it out and let the thread starter reach that conclusion by himself.

As the others have pointed out here, work is not just the force times the distance over which it is exerted on the mass. If you're more of a maths guy, this exact definition should help you:

W \equiv \vec F \cdot d \equiv |F||d|\cos{\theta}
Work is defined as the dot product of the force vector and the displacement vector. The dot product:
\vec A\cdot\vec B\equiv |A||B|\cos{\theta} where \theta is the angle between the two vectors.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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