What is the terminal speed for an 75.0kg skier going down a 35.0∘ snow-covered slope on wooden skis μk= 0.060?
Assume that the skier is 1.60m tall and 0.300m wide.
Express your answer using two significant figures with the appropriate units.
Area skier = A = (1.60m x 0.300m) = .48 m^2
D = (1/4)A*v^2
Fnet = D
The Attempt at a Solution
(mgsinθ) - (μk*mgcosθ) = (1/4)A*v^2
=> vterminal = sqrt((4((mgsinθ) - (μk*mgcosθ))) /A )
vterminal = sqrt((4((75.0 * 9.80 * sin(35)) - (.060 * 75.0 * 9.80 * cos(35))))/.48)
vterminal = 56.68 m/s = 57 m/s (rounded to 2 sig figs)
Mastering Physics says that this answer is wrong but I cannot find my error. I have checked over the problem and my solution about a dozen times. I figure more experienced eyes may help find my ruinous mistake. Thank you! :)