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**A skier 58.0kg coasts down a 25.0 degree uniform slope. A kinetic frictional force of 70.0N opposes her motion. At the top of the slope her speed is 3.60 m/s. What is her final speed at a distance 57.0 metres down the slope?**

Kinetic Energy = 1/2mv^2

V=Vi+at^2

F=ma

So far I decomposed the force of gravity portion, Fx = (58)(9.8)(cos25) and then I subtrated 70.0 N from that getting 445.145. At this point, I don't know what to do.