(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A sky diver of mass 83.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 46.0 m/s.

(a) What is the acceleration of the sky diver when her speed is 30.0 m/s?

2. Relevant equations

R=-bv

mg-bv=ma

3. The attempt at a solution

since R is the resistance force acting on the sky diver: R=mg

therefore I set:

83*9.8 = -b(46),

and solve for b, b = -17.683

then plug the same numbers back into mg-bv=ma to solve for the acceleration at 30m/s

(83)(9.8)-(17.683)(30)=(83)a

a = 3.41m/s^2

but this is not correct, can someone please tell me what i did wrong?

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# Homework Help: Terminal Velocity of a sky diver

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