Terminal Velocity of magnet down a copper tube

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SUMMARY

The discussion centers on calculating the terminal velocity of three magnets falling through a copper tube, with specific parameters including a tube length of 0.24m, a total magnet mass of 4.98x10-3kg, and a magnetic flux density of 428mT. The derived equation for electromotive force (e) is e=(B2L2v)/R, where R is the resistance of the copper tube at 1.77x10-4 ohms. The user reported a measured terminal velocity of 0.104m/s but calculated a significantly lower velocity of 8.2x10-4m/s, indicating a need for clarification on the constant of proportionality (C) in the alternative equation F = C(Bwv)/p.

PREREQUISITES
  • Understanding of electromagnetic principles, specifically Faraday's law of induction.
  • Familiarity with basic physics equations related to motion and forces.
  • Knowledge of electrical resistance and its calculation in conductive materials.
  • Basic algebra for manipulating equations and solving for variables.
NEXT STEPS
  • Research the concept of terminal velocity in magnetic systems.
  • Investigate the role of the constant of proportionality (C) in the equation F = C(Bwv)/p.
  • Learn about the effects of magnetic flux density on falling objects in conductive mediums.
  • Explore the derivation and application of Faraday's law in practical scenarios.
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Students studying physics, particularly those focusing on electromagnetism and motion dynamics, as well as educators seeking practical examples of these concepts in action.

krisal
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Homework Statement

I[/B]
I am trying to find an equation that relates the velocity of 3 magnet when it falls down a copper tube to my measurement.

The length of the copper tube is L=0.24m,
The total mass of the 3 magnet is m = 4.98x10-3kg
magnetic flux density B = 428mT,
the thickness of the tube w = 0.05cm
inner radius is r= 0.7cm,
the resistivity of the copper tube is p = 1.68x10-8 ohmm
resistance of copper tube is R= 1.77x10-4 ohms
and the terminal velocity that I measured is v = 0.104m/s

Homework Equations


I obtained this equation e=(B^2L^2v)/R from this procedure

e =Blv=IR
F = BIL rearranging for I = F/BL and sub to equation above
e=(B^2L^2v)/R

also

I found an equation in the internet that F = C(Bwv)/p which C is the constant of proportionality but it did not tell what C is.

The Attempt at a Solution


[/B]
I used the first equation but the answer for v is much smaller v = 8.2x10-4m/s
I would use the second equation but I do not know what C is

I want an equation that is not very complex to derive
 
Last edited by a moderator:
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Did you check the units of your answer? And where exactly does a speed occur there?
krisal said:
I want an equation that is not very complex to derive
Not all problems have easy answers.
 

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