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Terminal Velocity of magnet down a copper tube

  1. Mar 30, 2016 #1
    1. The problem statement, all variables and given/known dataI
    I am trying to find an equation that relates the velocity of 3 magnet when it falls down a copper tube to my measurement.

    The length of the copper tube is L=0.24m,
    The total mass of the 3 magnet is m = 4.98x10-3kg
    magnetic flux density B = 428mT,
    the thickness of the tube w = 0.05cm
    inner radius is r= 0.7cm,
    the resistivity of the copper tube is p = 1.68x10-8 ohmm
    resistance of copper tube is R= 1.77x10-4 ohms
    and the terminal velocity that I measured is v = 0.104m/s

    2. Relevant equations
    I obtained this equation e=(B^2L^2v)/R from this procedure

    e =Blv=IR
    F = BIL rearranging for I = F/BL and sub to equation above
    e=(B^2L^2v)/R

    also

    I found an equation in the internet that F = C(Bwv)/p which C is the constant of proportionality but it did not tell what C is.

    3. The attempt at a solution

    I used the first equation but the answer for v is much smaller v = 8.2x10-4m/s
    I would use the second equation but I do not know what C is

    I want an equation that is not very complex to derive
     
    Last edited by a moderator: Mar 30, 2016
  2. jcsd
  3. Mar 31, 2016 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Did you check the units of your answer? And where exactly does a speed occur there?
    Not all problems have easy answers.
     
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