Calculate Pressure Ratio of Helium and Argon with Equal Mass at Same Temperature

[Termodinamica]

Homework Statement

In 2 identical containers we have equal mass of helium and Argon at the same temperature.The ratio of the 2 pressures (pressure 1 and pressure 2) knowing that μ helium= 4 kg/kmol and μ argon= 40 kg/kmol is:
a 0.1 b 10 c 5 d 40 e 1/5

Homework Equations

i don't know

The Attempt at a Solution

i don't know

 

[grzz]

What macroscopic equation gives the behaviour of ideal gases?

 

[Termodinamica]

idk tell me
i got bad marks at physics

 

[grzz]

idk =?

 

[Termodinamica]

pv=nrt?
i don't know man physics is not my main thing

 

[grzz]

pV=nRT

Correct.

Now see what is identical in both cases and hence try to see on what physical quantity does p depend.

 

[Termodinamica]

p=nrt/v
?
can you please give more hints?

 

[grzz]

Temp is the same for both.
What else is the same?

 

[Termodinamica]

R constant and T
n is the quantity
EDIT:Was joking man i know how to do it p1v=m/miu RT

 

[grzz]

Correct.
But if you read the problem CAREFULLY you will notice that there is something else constant.

 

[Termodinamica]

HAHAAHAH man now i don't understand
p1v=U x R
??

 

[grzz]

Which gas has the bigger volume?

 

[Termodinamica]

Which gas has the bigger volume?

Argon i think.

 

[grzz]

is the argon in a bigger container?

 

[Termodinamica]

is the argon in a bigger container?

no. what to do?

 

[grzz]

Each gas in an IDENTICAL container. Hence the volume ...

 

[Termodinamica]

Ok so volume is constant.Here is what i made so far.
Find p1 and p2
P1=1/μ helium *R
P2=1/μ argon *R

and then P2/P1 = 10.

so from those answers: a) 0.1 b)10 c)5 d)40 e)1/5

the right one is b?

 

[grzz]

P argon/P helium = 0.1

 

[grzz]

P helium/P argon = 10

 

[Termodinamica]

P helium/P argon = 10

so its 10?
i did it good?
can you help me at the other problem too? :D

 

[grzz]

which problem?

 

[Termodinamica]

At boiling whit 1K(kelvin) of a gas whit constant pressure the volume is 3 times bigger.The initial temperature of the gas in this process has the value:
a. 6K b 0.5 K c 10K d 100K e 500K

 

[grzz]

Which equation gives the behaviour of an ideal gas?

 

[Termodinamica]

pv/t=p2v2/t2

 

[grzz]

Cross out the P because it is the same on both sides.

 

[Termodinamica]

yup so v/t = v2/t2 .
What i do next?

 

[grzz]

Now put in the values you know to get what you do not yet know.

 

[Termodinamica]

So T2= t1 +1k?
V2 = 3V1?
WE know that the second volume is 3x bigger then the first volume.